What is the exact value of sec -330? Trigonometry Inverse Trigonometric Functions Basic Inverse Trigonometric Functions 1 Answer sjc May 6, 2018 sec(-330)=(2sqrt3)/3 Explanation: sec(-330) -330" " will be in the first quadrant -330=+30 :.sec(-330)=sec30 sec30=1/cos30 because cos30=sqrt3/2 sec30=1/(sqrt3/2)=2/sqrt3 rationalising sec30=(2sqrt3)/3 Answer link Related questions What are the Basic Inverse Trigonometric Functions? How do you use inverse trig functions to find angles? How do you use inverse trigonometric functions to find the solutions of the equation that are in... How do you use inverse trig functions to solve equations? How do you evalute sin^-1 (-sqrt(3)/2)? How do you evalute tan^-1 (-sqrt(3))? How do you find the inverse of f(x) = \frac{1}{x-5} algebraically? How do you find the inverse of f(x) = 5 sin^{-1}( frac{2}{x-3} )? What is tan(arctan 10)? How do you find the arcsin(sin((7pi)/6))? See all questions in Basic Inverse Trigonometric Functions Impact of this question 4771 views around the world You can reuse this answer Creative Commons License