Question

What is the force, in terms of Coulomb's constant, between two electrical charges of `24 C` and `32 C` that are `12 m` apart?

Answer 1

If `q_1` and `q_2` are charges and `r` is the distance between them then the force `F` between them is given by

`F=(kq_1q_2)/r^2`

Where `k` is a constant and is known as Coulomb's force constant

Here Let `q_1=24C`, `q_2=32C` and `r=12m`,

`F=(k*24*32)/12^2`

`implies F=(768k)/144=`

`implies F=5.33kN`

Since the force is positive so the force between the charges is repullsive