Question

What is the formula for lead (IV) oxide?

Answer 1

Pb`O_2`

Explanation:

For each `Pb^(4+)` we need two negative oxide ions `O^(2-)` to balance out total positive and total negative charge.

The ratio of `Pb^(4+)` and `O^(2-)` ios is 1:2 and hence the formula is Pb`O_2`.