What is the formula of the compound formed when ammonium ions, $N H_{4}^{+}$ $NH_4 ^+$ , and phosphate ions, $P O_{4}^{3 -}$ $PO_4^(3-)$ combine?

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What is the formula of the compound formed when ammonium ions, $N H_{4}^{+}$ $NH_4 ^+$ , and phosphate ions, $P O_{4}^{3 -}$ $PO_4^(3-)$ combine?

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Answer 1 · 2017-02-26T16:27:10

${(N H_{4})}_{3} P O_{4}$ $(NH_4)_3PO_4$

Explanation:

This is because $N H_{4}^{+}$ $NH_4^(+)$ has a charge of 1+, and $P O_{4}^{3 -}$ $PO_4^(3-)$ has a charge of 3-. The compound should have a neutral charge, so it takes three $N H_{4}^{+}$ $NH_4^+$ to balance out $P O_{4}^{3 -}$ $PO_4^(3-)$ .

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What is the formula of the compound formed when ammonium ions, $N H_{4}^{+}$ $NH_4 ^+$ , and phosphate ions, $P O_{4}^{3 -}$ $PO_4^(3-)$ combine?

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What is the formula of the compound formed when ammonium ions, NH+4NH_4 ^+, and phosphate ions, PO3−4PO_4^(3-) combine?

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What is the formula of the compound formed when ammonium ions, $N H_{4}^{+}$ $NH_4 ^+$ , and phosphate ions, $P O_{4}^{3 -}$ $PO_4^(3-)$ combine?