Question

What is the frequency of `f(theta)= sin 12 t - cos 27 t`?

Answer 1

Period: `2pi`

Explanation:

Period of sin 12t --> (2pi)/12 = pi/6
Period of cos 27t ---> (2pi)/27
Period of f(t) --> least common multiple of `pi/6` and `(2pi)/27`
`pi/6` ...x (12) .... --> `2pi`
`(2pi)/27`....x ... (27) ... --> `2pi`
The period of f(t) is `2pi`. Find the frequency.