Question

What is the frequency of `f(theta)= sin 2 t - cos 12 t`?

Answer 1

`1/pi`

Explanation:

The period `(2pi)/2=pi` of `sin 2t` is

`6xx`(the period `(2pi)/12=pi/6`) of `cos 12t`.

So, the period for the compounded oscillation

`f(t)=sin 2t - cos 12t` is `pi`.

The frequency = 1/(period)=`1/pi`.