Question

What is the frequency of `f(theta)= sin 6 t - cos 4 t`?

Answer 1

`pi or 180^@`

Explanation:

The period (frequency) of `f(t1) = sin 6t` is `(2pi)/6 = pi/3` or `60^@`
The period of `f(t2) = cos 4t` is `(2pi)/4 = pi/2` or `90^@`
The common period is the least multiple of these 2 periods.
It is `pi` or `180^@.`