What is the fundamental period of 2 cos (3x)?

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Answer 1 · 2015-04-24T11:09:57

The fundamental period of $cos(theta)$
is $2pi$
That is (for example) $cos(0) " to " cos(2pi)$
represents one full period.

In the expression $2 cos(3x)$
the coefficient $2$ only modifies the amplitude.

The $(3x)$ in place of $(x)$
stretches the value of $x$ by a factor of $3$

That is (for example)
$cos(0) " to " cos(3*((2pi)/3))$
represents one full period.

So the fundamental period of $cos(3x)$ is
$(2pi)/3$

Answer 2 · 2015-04-24T11:14:15

$(2pi)/3$

Period of cos x is $2pi$ , hence period of cos 3x would be $(2pi)/3$ , which means it would repeat itself 3 times between 0 and $2pi$