What is the gram-formula mass of (NH4)3PO4?

1 Answer
Meave60
Jul 10, 2018

It is 149.087 g/mol.

Explanation:

Multiply the subscript for each element by its molar mass, which is its atomic weight in g/mol. In the case of (NH4)3, multiply the subscripts inside the parentheses by 3.

Gram-formula mass of (NH4)3PO4

(3×14.007 g/mol N)+(12×1.008 g/mol H)+(1×30.974 g/mol P)+(4×15.999 g/mol O)=

149.087 g/mol (NH4)3PO4

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