What is the implicit derivative of 3=1/y -x^2 ?

1 Answer
Jan 2, 2016

dy/dx = -2xy^2 The trick is in finding the derivative of each term, for term containing y find derivative as usual and put dy/dx next to it to indicate it is differentiated with respect to x

Explanation:

3 = 1/y - x^2

3 = y^-1 - x^2

Differentiate both sides with respect to x

d/dx(3) = d/dx(y^-1) - d/dx(x^2)

0 = -y^(-1-1)dy/dx - 2x

0=-y^-2dy/dx -2x

0= -1/y^2 dy/dx -2x

Add 2x to both the sides

2x = -1/y^2 dy/dx

Multiply both sides by -y^2

-2xy^2 = dy/dx

Answer dy/dx = -2xy^2