What is the implicit derivative of #3=1/y -x^2 #?

1 Answer
Jan 2, 2016

#dy/dx = -2xy^2# The trick is in finding the derivative of each term, for term containing #y# find derivative as usual and put #dy/dx# next to it to indicate it is differentiated with respect to #x#

Explanation:

#3 = 1/y - x^2#

#3 = y^-1 - x^2#

Differentiate both sides with respect to #x#

#d/dx(3) = d/dx(y^-1) - d/dx(x^2)#

#0 = -y^(-1-1)dy/dx - 2x#

#0=-y^-2dy/dx -2x#

#0= -1/y^2 dy/dx -2x#

Add 2x to both the sides

#2x = -1/y^2 dy/dx#

Multiply both sides by #-y^2#

#-2xy^2 = dy/dx#

Answer #dy/dx = -2xy^2#