What is the implicit derivative of #3=e^y-e^(2y) #?

1 Answer

Hey there!

To compute any implicit derivative, you always want to differentiate like you normally would with respect to x, but when taking the derivative of something with a "y" in it, you must multiply by y' or dy/dx. After that, isolate for dy/dx, then you're done! If you want to take the derivative with respect to it's the same idea!

Explanation:

In your example you have #3 = e^y - e^(2y) #:

First, take the derivative of everything with respect to x, but remember, when taking the derivative of a term with "y" in it, you must multiply by dy/dx:

# 0 = e^y*dy/dx - 2e^(2y)*dy/dx #

Factor out dy/dx:

# 0 = dy/dx(e^y - e^(2y)) #

Divide by #e^y - e^(2y) #on both sides:

# 0 = dy/dx#

That's the derivative (with respect to x)! Hopefully that helps! All in all, that's the process you should follow do calculate implicit derivatives!