What is the integral of #e^(0.5x)#? Calculus Introduction to Integration Integrals of Exponential Functions 2 Answers Harish Chandra Rajpoot Jul 18, 2018 #2e^{0.5x}+C# Explanation: #\int e^{0.5x}\ dx# #=\int e^{0.5x}1/0.5d(0.5x)# #=1/0.5\int e^{0.5 x}\ d(0.5x)# #=2e^{0.5x}+C# Answer link Sonnhard Jul 18, 2018 #2e^(1/2x)+C# Explanation: Substiting #t=1/2x# we get #x=2t# so #dx=2dt# and our integral is given by #2int e^tdt=2e^t+C=2e^(1/2x)+C# Answer link Related questions How do you evaluate the integral #inte^(4x) dx#? How do you evaluate the integral #inte^(-x) dx#? How do you evaluate the integral #int3^(x) dx#? How do you evaluate the integral #int3e^(x)-5e^(2x) dx#? How do you evaluate the integral #int10^(-x) dx#? What is the integral of #e^(x^3)#? What is the integral of #e^(2x)#? What is the integral of #e^(7x)#? What is the integral of #2e^(2x)#? How do I find the antiderivative of #f(x)=1/(e^(2x)-9)^(1/2)#? See all questions in Integrals of Exponential Functions Impact of this question 28489 views around the world You can reuse this answer Creative Commons License