What is the integral of $e^{0.5 x}$ $e^(0.5x)$ ?

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Answer 1 · 2018-07-18T14:01:08

$2 e^{0.5 x} + C$ $2e^{0.5x}+C$

$\int e^{0.5x}\ dx$

$=\int e^{0.5x}1/0.5d(0.5x)$

$=1/0.5\int e^{0.5 x}\ d(0.5x)$

$=2e^{0.5x}+C$

Answer 2 · 2018-07-18T14:05:18

$2e^(1/2x)+C$

Substiting $t=1/2x$ we get

$x=2t$ so $dx=2dt$ and our integral is given by $2int e^tdt=2e^t+C=2e^(1/2x)+C$

What is the integral of e^(0.5x)e0.5xe^(0.5x)?