What is the integral of #int e^((x^2)) dx #? Calculus Introduction to Integration Definite and indefinite integrals 1 Answer A. S. Adikesavan Nov 4, 2016 #=C+x+(1/3)x^3/(1!)+(1/5)x^5/(2!)+(1/7)x^7/(3!)+...# Explanation: Use #e^X=1+X+X^3/(2!)+X^3/(3!)|..# #inte^(x^2) dx# #=int (1+x^2/(1)+x^4/(2!)+x^6/(3!)+...)dx# #=C+x+(1/3)x^3/(1!)+(1/5)x^5/(2!)+(1/7)x^7/(3!)+...# Answer link Related questions What is the difference between definite and indefinite integrals? What is the integral of #ln(7x)#? Is f(x)=x^3 the only possible antiderivative of f(x)=3x^2? If not, why not? How do you find the integral of #x^2-6x+5# from the interval [0,3]? What is a double integral? What is an iterated integral? How do you evaluate the integral #1/(sqrt(49-x^2))# from 0 to #7sqrt(3/2)#? How do you integrate #f(x)=intsin(e^t)dt# between 4 to #x^2#? How do you determine the indefinite integrals? How do you integrate #x^2sqrt(x^(4)+5)#? See all questions in Definite and indefinite integrals Impact of this question 1071 views around the world You can reuse this answer Creative Commons License