Question

What is the integral of `int tan^4(x)sec^2(x)`?

Answer 1

`inttan^4xsec^2xdx=tan^5x/5+c`

Explanation:

Let `u=tanx`

`du=sec^2xdx`

Hence, `inttan^4xsec^2xdx`

= `intu^4du`

= `u^5/5+c`

= `tan^5x/5+c`