What is the integral of $\sqrt{x}$ $sqrt(x)$ ?

Question

94376 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2014-12-11T17:29:49

$\int \sqrt{x} d x$ $int sqrt{x} dx$

by rewriting the square-root as the 1/2-power,

$= \int x^{\frac{1}{2}} d x$ $=int x^{1/2}dx$

by Power Rule,

$= \frac{x^{\frac{3}{2}}}{\frac{3}{2}} + C$ $={x^{3/2}}/{3/2}+C$

by cleaning up a bit,

$= \frac{2}{3} x^{\frac{3}{2}} + C$ $=2/3x^{3/2}+C$

I hope that this was helpful.

What is the integral of sqrt(x)√xsqrt(x)?