Question

What is the interval of convergence of #sum {(x-7)^n}/{(n!)7^n} #?

Answer 1

Converges for all `x in RR`

Explanation:

`sum {(x-7)^n}/{(n!)7^n} = sum_{n=1}^oo((x-7)/7)^n/(n!) = e^{((x-7)/7)}`