What is the inverse cosine of sqrt2/2?

1 Answer
Oct 24, 2015

arccos(sqrt(2)/2)=pi/4arccos(22)=π4

Explanation:

"inverse cos" may also be written as cos^(-1)cos1 or "arccos"

If arccos(sqrt(2)/2) = thetaarccos(22)=θ

rArrcolor(white)("XXX")cos(theta) = sqrt(2)/2XXXcos(θ)=22

This is a standard ratio for the angle theta = pi/4θ=π4

Note: the inverse cosine is defined as having values restricted to the range [0,pi)[0,π) and therefore pi/4π4 is the only valid solution.