What is the inverse function of $f (x) = \frac{1}{7} x - 9$ $f(x)=1/7x-9$ ?

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Answer 1 · 2015-11-05T18:18:55

$\frac{9 + y}{7}$ $(9+y) / 7$

$y = \frac{1}{7} x - 9$ $y = 1/7x - 9$

// add 9 over
$9 + y = \frac{1}{7} x$ $9 + y = 1/7x$

// divide by 7
$\frac{9 + y}{7} = x$ $(9+y) / 7 = x$

The inverse of x is equal to:
$\frac{9 + y}{7}$ $(9+y) / 7$

What is the inverse function of f(x)=17x−9f(x)=1/7x-9?