What is the inverse function of #f(x)=x-2# and how do you find #f^-1(0)#?

1 Answer
Jul 28, 2015

#f^-1(x)=x+2#

#f^-1(0)=2#

Explanation:

Let #y=f(x)# where #y# is the image of an object #x#.

Then the inverse function #f^-1(x)# is a function whose objects are #y# and whose images are #x#

This means that we are trying to find a function #f^-1# that takes inputs as #y# and the result is #x#

Here's how we proceed

#y=f(x)=x-2#

Now we make #x# the subject of the formula

#=>x=y+2#

Hence #f^-1=x=y+2#

This means that the inverse of #f(x)=x-2# is #color(blue)(f^-1(x)=x+2)#

#=>f^-1(0)=0+2=color(blue)2#