What is the inverse of the function: #f(x) = 3x + 2#?

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Answer 1 · 2015-07-20T21:06:40

#f^-1(y) = (y-2)/3#

Let #y = f(x) = 3x+2#

Solve for #x# ...

Subtract #2# from both ends to get:

#y - 2 = 3x#

Divide both sides by #3# to get:

#x = (y-2)/3#

Hence #f^-1(y) = (y-2)/3#