What is the kinetic energy of an object with a mass of #3 kg# that has been in freefall for #28 s#?

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Answer 1 · 2015-12-21T00:16:14

#112.9"kJ"#

We need to get the velocity of the object after it has fallen under gravity for 28s.

We can use #v=u+at#

This becomes:

#v=0+9.8xx28#

#:.v=274.4"m/s"#

The kinetic energy is given by:

KE = #1/2mv^2#

#:."KE"=1/2xx3xx274.4^(2)=112,943"J"#

#=112.9"kJ"#