What is the kinetic energy of an object with a mass of $3 kg$ that has been in freefall for $28 s$ ?

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Answer 1 · 2015-12-21T00:16:14

$112.9"kJ"$

We need to get the velocity of the object after it has fallen under gravity for 28s.

We can use $v=u+at$

This becomes:

$v=0+9.8xx28$

$:.v=274.4"m/s"$

The kinetic energy is given by:

KE = $1/2mv^2$

$:."KE"=1/2xx3xx274.4^(2)=112,943"J"$

$=112.9"kJ"$

What is the kinetic energy of an object with a mass of 3 kg3 kg that has been in freefall for 28 s28 s?