What is the length of the arc subtended by the central angle of $240^{\circ}$ $240^circ$ , when such arc is located on the Unit Circle?

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What is the length of the arc subtended by the central angle of $240^{\circ}$ $240^circ$ , when such arc is located on the Unit Circle?

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Answer 1 · 2017-03-24T11:42:05

The length of the arc is $4.19 (2 d p)$ $4.19(2dp)$ unit .

Explanation:

The circumference of unit circle $(r = 1)$ $(r=1)$ is $2 \cdot π \cdot r = 2 \cdot π \cdot 1 = 2 \cdot π$ $2*pi*r=2*pi*1=2*pi$ unit

The length of the arc subtened by central angle of $240^{0}$ $240^0$ is $l_{a} = 2 \cdot π \cdot \frac{240}{360} \approx 4.19 (2 d p)$ $l_a=2*pi*240/360 ~~ 4.19(2dp)$ unit . [Ans]

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What is the length of the arc subtended by the central angle of $240^{\circ}$ $240^circ$ , when such arc is located on the Unit Circle?

1 Answer

Explanation:

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What is the length of the arc subtended by the central angle of 240^circ240∘240^circ, when such arc is located on the Unit Circle?

1 Answer

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What is the length of the arc subtended by the central angle of $240^{\circ}$ $240^circ$ , when such arc is located on the Unit Circle?