What is the limit of $7/4(x-1)^2$ as x approaches 1?

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Answer 1 · 2018-04-16T16:56:42

$lim_(x->1) 7/4(x-1)^2=0$

We know that $f(x)=7/4(x-1)^2=0$ is continuous over its domain.

So $lim_(x->c)f(x)=f(c)$ for all $x$ in the domain of $f$ .

Thus

$lim_(x->1) 7/4(x-1)^2=7/4(1-1)^2=0$

What is the limit of 7/4(x-1)^27/4(x-1)^2 as x approaches 1?