Question

What is the limit of `cos (1/x)` as x approaches infinity?

Answer 1

`Lt_(x->oo)cos(1/x)=1`

Explanation:

As `x->oo`, `1/x->0`

Therefore, as `x->oo`, `cos(1/x)->cos0=1`

Hence, `Lt_(x->oo)cos(1/x)=1`