What is the mass (in grams) of 8.34 moles calcium acetate?

1 Answer
anor277
Dec 29, 2015

One mole of Ca{O(O=)C-CH_3}_2 has a mass of 158.17 g.

Explanation:

So, if there are 8.34 mol calcium acetate, there are 8.34*cancel(mol)xx158.17*g*cancel(mol^-1) ~= 1300 g.

But please don't trust my 'rithmetic.

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