What is the mass of $2.30 x 10^{24}$ $2.30 x 10^24$ formula units of magnesium chloride?

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What is the mass of $2.30 x 10^{24}$ $2.30 x 10^24$ formula units of magnesium chloride?

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Answer 1 · 2016-11-20T16:28:48

$Mass$ $"Mass"$ $≅$ $~=$ $380 \cdot g$ $380*g$

Explanation:

Here we use $N_{A}$ $N_A$ , $Avogadro's number$ $"Avogadro's number"$ as our counting number, where $N_{A} = 6.022 \times 10^{23} \cdot m o l^{- 1}$ $N_A=6.022xx10^23*mol^-1$ .

$Avogadro's number$ $"Avogadro's number"$ of $M g C l_{2}$ $MgCl_2$ formula units have a mass of $95.21 \cdot g$ $95.21*g$ . Alternatively we say the molar mass of $M g C l_{2}$ $MgCl_2$ is $95.21 \cdot g \cdot m o l^{- 1}$ $95.21*g*mol^-1$ .

So we work out the quotient,

$\frac{2.30 \times 10^{24}}{6.022 \times 10^{23} \cdot m o l^{- 1}} \times 95.21 \cdot g \cdot m o l^{- 1} ≅ 4 \times 95.21 \cdot g$ $(2.30xx10^24)/(6.022xx10^23*mol^-1)xx95.21*g*mol^-1~=4xx95.21*g$

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What is the mass of $2.30 x 10^{24}$ $2.30 x 10^24$ formula units of magnesium chloride?

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