What is the mass of one mole of ${(N H_{2})}_{3} P O_{4}$ $(NH_2)_3PO_4$ ?

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Answer 1 · 2016-08-03T19:22:00

Of $ammonium phosphate, 149.09 \cdot g \cdot m o l^{- 1}$ $"ammonium phosphate, "149.09*g*mol^-1$

The salt you have written would not be isolable from water. $Ammonium phosphate$ $"Ammonium phosphate"$ is ${(N H_{4})}_{3} P O_{4}$ $(NH_4)_3PO_4$

$Ammonium biphosphate {(N H_{4})}_{2} H P O_{4}$ $"Ammonium biphosphate "(NH_4)_2HPO_4$ is commonly used as an agricultural fertilizer.

What is the mass of one mole of (NH2)3PO4(NH_2)_3PO_4?