What is the midpoint of (2,-2, 4) and (-2,0, 6)?

Please help!!

1 Answer
Jim G.
May 22, 2018

#(0,-1,5)#

Explanation:

#"given endpoints say"#

#(x_1,y_1,z_1)"and "(x_2,y_2,z_2)" then"#

#"midpoint "=[1/2(x_1+x_2),1/2(y_1+y_2),1/2(z_1+z_2)]#

#"let "(x_1,y_1,z_1)=(2,-2,4),(x_2,y_2,z_2)=(-2,0,6)#

#"midpoint "=[1/2(2-2),1/2(-2+0),1/2(4+6)]#

#color(white)("midpoint ")=(0,-1,5)#

Related questions
Impact of this question
685 views around the world
You can reuse this answer
Creative Commons License