What is the minimum mass of oxygen, in grams, needed to burn 16.4 g #"C"_4"H"_12"O"#?

Question

Give your answer to three significant figures.

The unbalanced chemical equation is

#"C"_4"H"_10"O"+"O"_2->"CO"_2+"H"_2"O"#

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Answer 1 · 2017-09-27T06:35:24

We will use butanol.....

#C_4H_10O(l) + 6O_2(g) rarr 4CO_2(g) + 5H_2O(l)#

Is this balanced with respect to mass and charge? Do not trust my arithmetic!

And so #"moles of butanol"=(16.4*g)/(74.12*g*mol^-1)=0.221*mol#

And so with respect to dioxygen, we need a mass of....

#0.221*molxx6xx32.00*g*mol^-1=42.5*g#.