What is the missing coefficient in the balanced equation? What type of reaction is it? Mg(OH)_2 + H_2SO_4 -> MgSO_4 + ?H_2OMg(OH)2+H2SO4MgSO4+?H2O

1 Answer
May 22, 2017

The stoichiometrically balanced equation is:

Mg(OH)_2 + H_2SO_4 rarr MgSO_4 + color(red)2H_2OMg(OH)2+H2SO4MgSO4+2H2O

And this is an acid-base reaction.

Explanation:

Chemical equations are balanced with respect to mass and charge. For every reactant particle, there is a corresponding product particle. And for every reactant charge, there must be a corresponding product charge. When you come to study "redox reactions"redox reactions we introduce the electron as a conceptual particle with a negative charge so that redox reactions can also be shown to conserve charge:

"Reduction:"Reduction:

O_2(g) + 4e^(-) rarr 2O^(2-)O2(g)+4e2O2 (i)(i)

"Oxidation:"Oxidation:

Fe(s) rarr Fe^(2+) +2e^(-)Fe(s)Fe2++2e (ii)(ii)

And we cross multiply these individual redox reactions so that the electrons do not appear in the final redox equation:

(i) + +2xx(ii)(i)++2×(ii) gives.................

2Fe(s) +O_2+cancel(4e^(-)) rarr 2FeO +cancel(4e^(-))

2Fe(s) +O_2 rarr 2FeO

Charge is balanced, and mass is balanced. As is ABSOLUTELY required.

In the given example, we could write the net ionic equation, i.e.

H_3O^(+) + HO^(-) rarr 2H_2O

Are mass and charge conserved here?