What is the molar mass of iron (III) oxide ( $F e_{2} O_{3}$ $Fe_2O_3$ )?

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Answer 1 · 2016-12-26T15:55:09

$159.70 \frac{g}{m o l}$ $159.70 g/(mol)$

$We will use the formula below to answer the question:$ $color(purple)"We will use the formula below to answer the question:"$

atomic weight of element $\times$ $xx$ number of atoms given by subscript #= molar mass

First, you want to have a periodic table available so you can determine the atomic weight of Fe and O:

From the chemical formula, there are 2 iron atoms, so the atomic mass has to be multiplied by 2, which gives you a value of 111.7 g/mol

Next, you have 3 oxygen atoms, so you would multiply the atomic mass of O by 3 to obtain an atomic weight of 48.00 g/mol

Now you want to add the mass of each atom together to obtain the molar mass of the entire compound:

$111.7 g/mol + 48.00 g/mol = 159.70 g/mol$ $color (magenta) ("111.7 g/mol + 48.00 g/mol = 159.70 g/mol")$

What is the molar mass of iron (III) oxide (Fe2O3Fe_2O_3)?