What is the molar ratio for the chemical reaction $A l + O_{2} \to A l_{2} O_{3}$ $Al + O_2 -> Al_2O_3$ ?

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Answer 1 · 2015-12-20T02:22:10

Aluminum to oxygen is 0.666

Balance the equation

4Al + $3 O_{2} \to 2 A l_{2} O 3$ $3O_2 rarr 2Al_2O3$

In the reactant side 4 Al reacts with six oxygen atoms to for two molecules of $A l_{2} O_{3}$ $Al_2O_3$

Mole ratio Al to oxygen = No of atoms of Al in $A l_{2} O_{3}$ $Al_2O_3$ $\div$ $-:$ No of atoms of Oxygen in $A l_{2} O_{3}$ $Al_2O_3$

Hence Al to O2 mole ratio 2 $\div$ $-:$ 3 = 0.666

What is the molar ratio for the chemical reaction Al+O2→Al2O3Al + O_2 -> Al_2O_3?