Question

What is the molarity of .450 mol of `NaOH` in 1.65 L of solution?

Answer 1

`"Concentration"="Moles of solute"/"Volume of solution"`

Explanation:

`"Concentration"=(0.450*mol)/(1.65*L)` `~=` `0.3*mol*L^-1` with respect to sodium hydroxide. What is the `pH` of this solution?