What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for methanol is $C H_{3} O H$ $CH_3OH$ .

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Answer 1 · 2017-02-11T16:41:48

$The mole fraction of methanol is$ $"The mole fraction of methanol is"$ $\frac{2}{3}$ $2/3$ .

$χ_{MeOH}$ $chi_"MeOH"$ $=$ $=$ $\frac{Moles of MeOH}{Moles of methanol + moles of water}$ $"Moles of MeOH"/"Moles of methanol + moles of water"$

$\frac{6.0 \cdot m o l}{(6.0 + 3.0) \cdot m o l} = \frac{2}{3}$ $(6.0*mol)/((6.0+3.0)*mol)=2/3$ as required.............

What is the $mole fraction of water?$ $"mole fraction of water?"$

What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for methanol is CH3OHCH_3OH.