What is the mole fraction of solute in a 3.37 $m$ $m$ aqueous solution?

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What is the mole fraction of solute in a 3.37 $m$ $m$ aqueous solution?

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Answer 1 · 2018-06-07T14:55:51

$χ_{solute} \equiv 0.0572$ $chi_"solute"-=0.0572$

Explanation:

We gots a solute that has a MOLAL concentration of $3.37 \cdot m o l \cdot k g^{- 1}$ $3.37*mol*kg^-1$ ...and so in $1 \cdot k g$ $1*kg$ of WATER there are $3.37 \cdot m o l$ $3.37*mol$ ...

Now $χ_{solute} = \frac{moles of solute}{total mole in solution}$ $chi_"solute"="moles of solute"/"total mole in solution"$

$\frac{3.37 \cdot m o l}{3.37 \cdot m o l + \frac{1000 \cdot g}{18.01 \cdot g \cdot m o l^{- 1}}} = 0.0572$ $(3.37*mol)/(3.37*mol+(1000*g)/(18.01*g*mol^-1))=0.0572$

What is $χ_{water}$ $chi_"water"$ ?

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What is the mole fraction of solute in a 3.37 $m$ $m$ aqueous solution?

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What is the mole fraction of solute in a 3.37 $m$ $m$ aqueous solution?