What is the molecular formula of a compound that has a molecular mass of 54 and the empirical formula C2H3?

1 Answer
anor277
May 14, 2017

C4H6.............

Explanation:

The molecular formula is always a whole number multiple of the empirical formula.

i.e. molecular formula=n×(empirical formula)

54⋅g⋅mol−1=n×(2×12.011+3×1.00794)⋅g⋅mol−1

=n×(27.04)⋅g⋅mol−1

Clearly, n=54.0⋅g⋅mol−127.04⋅g⋅mol−1=2

Molecular formula=(C2H3)×2=C4H6 as required.

This compound has two degrees of unsaturation, so it is a butadiene, or a cylocbutene, or an allene derivative, or an alkyne.........

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