What is the molecular formula of each compound CH2 with molar mass 42.08 g/mol?

1 Answer
Jul 8, 2018

Don't we got C_3H_6C3H6...I,e, probably propylene...

Explanation:

The "empirical formula"empirical formula is the simplest, whole number ratio defining constituent atoms in a species. The "molecular formula"molecular formula is a whole number multiple of the "empirical formula"empirical formula, and of course the multiple MIGHT be ONE.

And thus...."molecular formula"=nxx{"empirical formula"}molecular formula=n×{empirical formula}

And we take the relevant masses...

[(2xx12.011+4xx1.00794)*g*mol^-1]xxn-=underbrace(42.08*g*mol^-1)_"given molecular mass"

And so we solve for n by the quotient....

n=(42.08*g*mol^-1)/[1xx12.011+2xx1.00794*g*mol^-1]=3

And so our molecular formula is 3xxCH_2-=C_3H_6...this is propylene, or cyclopropane...