What is the name of $A g_{2} O$ $Ag_2O$ ?

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Answer 1 · 2016-05-12T22:33:41

Here's my thought process:

From formula: $Ag$ $"Ag"$ $\to$ $->$ silver, just from looking at the periodic table.
$O$ $"O"$ : second column from neon, so the oxidation state is $^{- 2}$ $""^(-2)$ since it would want to gain two electrons as a free element to get an octet valency.
This is a combination of a metal ( $Ag$ $"Ag"$ ) and nonmetal ( $O$ $"O"$ ) $\to$ $->$ ionic compound.
Ionic compound $\to$ $->$ oxidation state of $O$ $"O"$ $=$ $=$ actual charge. Thus, the charge on oxygen is $^{2 -}$ $""^(2-)$ . $\to$ $->$ anion
$O$ $"O"$ : anion stem = "ox"
Anion ending in an ionic compound: "-ide"
There are two equivalents of silver, due to the $_{2}$ $color(blue)(""_2)$ subscript.
The charge on silver for the neutral ${Ag}_{2} O$ $"Ag"_2"O"$ is gotten from solving $color(blue)(2)stackrel("Ag")overbrace((""^(?+))) + stackrel("O")overbrace((""^(2-))) = 0$ for $"?"$ .
Thus, the charge on silver is $color(blue)(""^(1+))$ .

Knowing the charge, and recalling the roman numeral for $""^(1+)$ is $\mathbf("I")$ , we now have the name.

Name:
cation name + roman numeral in parentheses + anion stem + anion ending

Silver + (I) + ox + ide

$->$ Silver(I) oxide

What is the name of Ag_2OAg2OAg_2O?