What is the norm or $< 5, 2, - 7 >$ $<5,2,-7 >$ ?

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Answer 1 · 2017-01-21T14:31:27

The answer is $= \sqrt{78}$ $=sqrt78$

The norm of a vector $< a, b, c >$ $<a,b,c>$ is

$| | < a, b, c > | | = \sqrt{a^{2} + b^{2} + c^{2}}$ $||< a, b , c>|| =sqrt(a^2+b^2+c^2)$

Therefore,

$| | < 5, 2, - 7 > | | = \sqrt{25 + 4 + 49} = \sqrt{78}$ $||<5,2,-7>|| =sqrt(25+4+49)=sqrt78$

What is the norm or <5,2,−7><5,2,-7 >?