What is the norm or $< - 7, 6, - 1 >$ $<-7 ,6,-1 >$ ?

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Answer 1 · 2016-06-11T21:44:57

$\sqrt{86}$ $sqrt86$

Let $x=(x_1,x_2,....,x_n)$ be any vector in an n-dimensional vector space X.
Then the norm of $x$ is given by

$||x||=sqrt(x_1^2+x_2^2+.....+x_n^2)$ .

So in this particular case we work in a 3-dimesnional vector space and get that

$||(-7;6;1)||=sqrt((-7)^2+6^2+(-1)^2$

$=sqrt86$

What is the norm or <-7 ,6,-1 ><−7,6,−1><-7 ,6,-1 >?