What is the number of oxygen atoms in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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What is the number of oxygen atoms in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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Answer 1 · 2017-05-11T01:00:41

There are 12 oxygen atoms in one formula unit of ${Al(SO}_{4})_{3}$ $"Al(SO"_4)_3"$ .

Explanation:

The subscript for the sulfate ion $({SO}_{4}^{2 -})$ $("SO"_4"^(2-))$ is $3$ $3$ . The subscript for the oxygen atom is $4$ $4$ . Multiply them together to determine the number of oxygen atoms in one formula unit of aluminum sulfate. $(3 \times 4 = 12)$ $(3xx4=12)$

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What is the number of oxygen atoms in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?

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What is the number of oxygen atoms in Al2(SO4)3Al_2(SO_4)_3?

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What is the number of oxygen atoms in $A l_{2} {(S O_{4})}_{3}$ $Al_2(SO_4)_3$ ?