What is the oxidation number of chlorine atom in $H C l$ $HCl$ , $C l_{2}$ $Cl_2$ , and $H C l O$ $HClO$ ?

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What is the oxidation number of chlorine atom in $H C l$ $HCl$ , $C l_{2}$ $Cl_2$ , and $H C l O$ $HClO$ ?

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Answer 1 · 2017-01-01T14:05:58

In $H C l$ $HCl$ we have $C l (- I)$ $Cl(-I)$ .............

Explanation:

In $C l_{2}$ $Cl_2$ , $C l (0)$ $Cl(0)$ , and in $H C l O$ $HClO$ , $C l (+ I)$ $Cl(+I)$ .

The oxidation number is the charge left on the central atom when all of the bonds are removed, with the charge devolved to the most electronegative atom.

For a homonuclear diatomic molecules, each atom has EQUAL electronegativity, and the charge is assumed to be shared; i.e. $C l_{2} \to 2 \times C l \cdot$ $Cl_2 rarr 2xxCl*$ ; $H C l \to H^{+} + C l^{-}$ $HCl rarr H^+ + Cl^-$ ; $H C l O \to H^{+ I} + C l^{+ I} + O^{+ I I}$ $HClO rarr H^(+I) + Cl^(+I)+O^(+II)$ .

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What is the oxidation number of chlorine atom in $H C l$ $HCl$ , $C l_{2}$ $Cl_2$ , and $H C l O$ $HClO$ ?

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What is the oxidation number of chlorine atom in $H C l$ $HCl$ , $C l_{2}$ $Cl_2$ , and $H C l O$ $HClO$ ?