Question

What is the oxidation state of an individual sulfur atom in `BaSO_4`?

Answer 1

`S(VI+)`

Explanation:

The oxidation state of sulfur in `SO_4^(2-)` is calculated by taking the charge of the ion, `-2`, and subtracting the oxidation number of oxygen, which is typically `-II`.

Thus `-2=S_"ON"-4xx(-2)` `=` `??`