What is the oxidation state of each element in $K_2Cr_2O_7$ ?

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Answer 1 · 2017-03-04T17:52:16

The sum of the oxidation numbers of the constituent elements is ZERO..........

And, following the normal rules, we have $K^(+I)$ , $Cr^(VI+)$ , and $O^(-II)$ ............

What about $CrO_3$ ?

What is the oxidation state of each element in K_2Cr_2O_7K_2Cr_2O_7?