What is the partial pressure of "CO"_2CO2 in a container that holds 5 moles of "CO"_2CO2, 3 moles of "N"_2N2, and 1 mole "H"_2H2 and has a total pressure of 1.05 atm?

1 Answer
1s2s2p
May 18, 2018

p("CO"_2)=0.58"atm"p(CO2)=0.58atm

Explanation:

p("CO"_2)="Total pressure"*"Mole fraction of CO"_2=1.05*5/(5+3+1)=1.05*5/9=0.58"atm"p(CO2)=Total pressure⋅Mole fraction of CO2=1.05⋅55+3+1=1.05⋅59=0.58atm

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