What is the percent by mass of oxygen in $M {g (N O_{3})}_{2}$ $Mg(NO_3)_2$ ?

Question

What is the percent by mass of oxygen in $M {g (N O_{3})}_{2}$ $Mg(NO_3)_2$ ?

1 Answer

Impact of this question

3046 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-01-30T08:15:40

$% O ≅ 65 %$ $%O~=65%$

Explanation:

$Percentage oxygen$ $"Percentage oxygen"$ $=$ $=$ $\frac{Mass of oxygen}{Molar mass of compound} \times 100 %$ $"Mass of oxygen"/"Molar mass of compound"xx100%$

$\frac{6 \times 15.999 \cdot g \cdot m o l^{- 1}}{148.32 \cdot g \cdot m o l^{- 1}} \times 100 % = ? ?$ $(6xx15.999*g*mol^-1)/(148.32*g*mol^-1)xx100%=??$

Science

Math

Humanities

... and beyond

What is the percent by mass of oxygen in $M {g (N O_{3})}_{2}$ $Mg(NO_3)_2$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

What is the percent by mass of oxygen in Mg(NO3)2Mg(NO_3)_2?

1 Answer

Explanation:

Related questions

Impact of this question

What is the percent by mass of oxygen in $M {g (N O_{3})}_{2}$ $Mg(NO_3)_2$ ?