What is the percent difference between the acceleration due to gravity at sea level and at the uppermost peak of Mount Everest?

1 Answer
Meave60
Dec 9, 2014

Percent difference is the difference between two values divided by the average of the two values times 100.

The acceleration due to gravity at sea level is #"9.78719 m/s"^2#.
The acceleration due to gravity at the top of Mount Everest is #"9.766322 m/s"^2#. http://www.physicsclassroom.com/class/1DKin/Lesson-5/Acceleration-of-Gravity

Average = (#"9.78719 m/s"^2 + "9.766322 m/s"^2"#)#/##"2"# = #"9.77676m/s"^2#

Percent difference = (#"9.78719 m/s"^2 - "9.766322 m/s"^2"#)#-:##"9.77676m/s"^2# x #"100"# = #"0.21347%"#

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