What is the percent of increase from 270cm³ to 750cm³?

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What is the percent of increase from 270cm³ to 750cm³?

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Answer 1 · 2016-06-04T20:15:10

$177.77 ¯ 7 %$ $177.77bar7%$ not accurate solution.

$177 \frac{7}{9} %$ $177 7/9 %$ accurate solution.

Explanation:

Method $\to \frac{difference}{original value} \times 100$ $-> ("difference")/("original value")xx100$

$\Rightarrow \frac{750 - 270}{270} \times 100 = 177.77 ¯ 7 %$ $=> (750-270)/270xx100 = 177.77bar7%$

The bar over the last 7 means it goes on repeating for ever.
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
There is a trick you can use to deal with repeating decimals
You convert them to fractions. Sometimes you need to multiply by a different value: $10^{n}$ $10^n$ as appropriate

Let $x = 177.77 ¯ 7$ $x=177.77bar7$

The $10 x = 1777.77 ¯ 7$ $10x=1777.77bar7$

So $10 x - x \to 1777.77 ¯ 7$ $10x-x ->1777.77bar7$
$" "ul(" "177.77bar7)" "larr" subtract"$
$" "1600$

So $9x=1600 => x= 1600/9 = 177 7/9 %$

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What is the percent of increase from 270cm³ to 750cm³?

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