Question

What is the percentage composition of `Ba(NO_3)_2`?

Answer 1

In order to find the percentage composition of different elements in Barium Nitrate , we need to know the number of moles of different elements in one mole of a compound

1 mole of Barium Nitrate has One mole of Barium ions, two moles of Nitrate ions.

Mass of One mole of Barium Nitrate is 261.4 g /mol

Mass of One mole of `Ba^(2+)` ions is 137.3 g /mol

Mass of Two mole of Nitrate ions is 124.0 g / mol

Mass % of `Ba^(2+)` ions = Mass of One mole of `Ba^(2+)` ions \ mass of one mole of Barium Nitrate

Mass % of `Ba^(2+)` ions = ( 137.3 g \ 261.4 g ) x 100

                                         =  52.5 %

Mass % of `(`N`O_3`)^(2+)# ions = ( 62.0 x 2 g \ 261.4 g ) x 100

                                         = 47.5%