What is the perimeter of a triangle with corners at #(6 ,5 )#, #(9 ,1 )#, and #(3 ,4 )#?

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Answer 1 · 2016-07-03T19:28:37

It is #12.4#.

We need to find the distances between the points.
We start assigning a letter to each point

#A=(6,5), B=(9,1), C=(3,4)#

The distances are

#AB=sqrt((6-9)^2+(5-1)^2)=sqrt(9+16)=5#

#AC=sqrt((6-3)^2+(5-4)^2)=sqrt(9+1)\approx3.16#

#BC=sqrt((9-3)^2+(1-4)^2)=sqrt(9+9)\approx4.24#.

The perimeter is then

#AB+AC+BC=5+3.16+4.24=12.4#.